Electron-Configuration Diagram for Aluminum


The Electron-Configuration Diagram for Aluminum 

The first step in the process is to detemine the number of electrons in the orbital-filling diagram of aluminum. Aluminum's atomic number 13 identifies the electron count in its orbital-filling diagram. The second step is to determine aluminum's short-hand element. Neon is aluminum's short-hand element and it is the preceding nobel element. A second method for finding the shorthand element is counting backward on the periodic table starting from aluminum. Aluminum's number of valence electrons can be found by subtracting neon's electron count(10) from aluminum’s electron count(13): 13-10=3. Aluminum has three valence electrons. See the the orbital-filling diagram in figure 2. In this case the valence shell is written as 3s²3p¹. All the sublevels filled after the s and before the p in the valence shell would be included in the electron-configuration diagram. In the case of aluminum there are no orbitals filled after the s and before the p. The last ten remaining electrons are in the kernel. The noble element that has just ten electrons is neon. The electron-configuration diagram in figure 2 for aluminum is [Ne]3s²3p¹.


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